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Grade 10th · Mathematics · Pair of Linear Equations in Two Variables

Linear Equations in Two Variables: Complete Concept Map & Formulas — Class 10 Maths

Master Pair of Linear Equations in Two Variables for Class 10 Maths. Complete concept map, consistency conditions table (intersecting, coincident, parallel lines), algebraic solution methods (substitution, elimination), and NCERT formulas.

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Essential Formulas & Mathematical Definitions

Standard Form: a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0
Intersecting Lines (Unique Solution / Consistent): a₁/a₂ ≠ b₁/b₂
Coincident Lines (Infinitely Many Solutions / Consistent): a₁/a₂ = b₁/b₂ = c₁/c₂
Parallel Lines (No Solution / Inconsistent): a₁/a₂ = b₁/b₂ ≠ c₁/c₂

Concept Map: System Classification & Ratio Conditions

A system of two linear equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 can be fully classified by inspecting coefficient ratios: 1. Unique Solution (Consistent): a₁/a₂ ≠ b₁/b₂. Graphically, the two lines intersect at exactly one point (x, y). 2. Infinitely Many Solutions (Consistent & Dependent): a₁/a₂ = b₁/b₂ = c₁/c₂. Graphically, the two lines coincide (overlap completely). 3. No Solution (Inconsistent): a₁/a₂ = b₁/b₂ ≠ c₁/c₂. Graphically, the lines are parallel and never meet.

Algebraic Method 1: Substitution Method

Step 1: Express one variable (say y) in terms of the other variable (x) from equation (1): y = (–c₁ – a₁x) / b₁. Step 2: Substitute this value of y into equation (2). This transforms equation (2) into a linear equation in one variable (x). Step 3: Solve for x. Step 4: Substitute the obtained x back into the expression from Step 1 to determine y.

Algebraic Method 2: Elimination Method (Most Efficient)

Step 1: Multiply one or both equations by suitable non-zero constants so that the coefficients of one variable (either x or y) become numerically equal. Step 2: Add or subtract the equations to eliminate that variable. Step 3: Solve the resulting single-variable equation. Step 4: Substitute the value back into any original equation to solve for the second variable.

Equations Reducible to a Pair of Linear Equations

When variables appear in denominators (e.g., 2/x + 3/y = 13), introduce auxiliary substitute variables: let u = 1/x and v = 1/y. Solve the linear system in u and v, then take reciprocals to find x = 1/u and y = 1/v.

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Exam Day Revision & Problem Solving Checklist

  • ✓Convert equations into standard form (ax + by + c = 0) before identifying coefficients a₁, b₁, c₁
  • ✓Always check the ratio test a₁/a₂ vs b₁/b₂ first before attempting algebraic solutions
  • ✓Remember that coincident lines (infinitely many solutions) are termed 'dependent consistent'
  • ✓In speed-distance upstream/downstream problems: Upstream speed = (x - y) km/h, Downstream speed = (x + y) km/h
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High-Yield Exam Strategy & Scoring Tips

Step-by-Step Mark Allocation

Always state the governing principle or formula first, write given values with standard SI units, substitute clearly, and highlight the final numerical answer with units in a box for full step marking.

Common Calculation Traps

Watch for unit prefixes (cm to m, minutes to seconds, g to kg, degrees to radians). In coordinate and ray optics problems, double-check Cartesian sign conventions before computing.

Recommended Practice & Calculation Tools

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Frequently Asked Exam Questions & Concept Clarifications

What is the condition for parallel lines in linear equations Class 10?

The condition for two lines to be parallel (having no solution and being inconsistent) is: a₁/a₂ = b₁/b₂ ≠ c₁/c₂.

What is the difference between consistent and inconsistent systems?

A consistent system has at least one solution (either a single unique solution if lines intersect, or infinitely many solutions if lines coincide). An inconsistent system has zero solutions because the lines are parallel and never intersect.

How to verify if a linear equation solution is correct?

Substitute the calculated values of x and y into both original equations. If both left-hand sides equal their respective right-hand sides, the solution is verified.